how to catch python syntx error

Question

try:
    pattern=r'<tr><td><a href='(?P<link>[\s\S]*?)'[\s\S]*?><img src='(?P<img>[\s\S]*?)'     width='130' height='130'[\s\S]*?/></a></td>'
except:
    try:
        pattern=r"<tr><td><a href='(?P<link>[\s\S]*?)'[\s\S]*?><img src='(?P<img>[\s\S]*?)' width='130' height='130'[\s\S]*?/></a></td>"
    except:
        pattern=r"""<tr><td><a href='(?P<link>[\s\S]*?)'[\s\S]*?><img src='(?P<img>[\s\S]*?)' width='130' height='130'[\s\S]*?/></a></td>"""

i'm write some regual expression through tool,and then generate python code,there are some situation need use ' or " or """ to wrap the regualar expression,and i want to try except the error,if the error capture then i can try another ,but seems it didn't work,anyone could help me ,thanks

Answer 1

You need to escape your quotes inside the RE. In your first line, all the single quotes need to be escaped as \'.

Don't use a try block to fix your faulty RE. Just do it right the first time.

Answer 2

The try/except statement in Python is used for errors that happen while your program is running. On the other hand, you are encountering errors that happen during compilation. In this case, try/except will not help you.

It looks like you would be best off always using """ to surround your regular expressions that contain different kinds of quotes. In Python, the only thing you can't put inside a triple-quoted string is a triple-quote.