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Answer 1

A:

give a class ('layers' for example) to each layer in order to collect them all together. Then loop them to find the first non visible and get the id.

var free = undefined;

$('.layers').each(function()
{
    if(!$(this).is(':visible'))
    {
        free = $(this).attr('id');
        break;
    }
});

if(free != undefined)
    alert('layer '+free+' is free');
else
    alert('there are no free layers');

Dalen 2010-10-12 07:07:49

Your answer seems fine.But sir, I intend to know what is wrong with my logic Thanks for your reply

Anant 2010-10-12 07:18:26

it is not scalable, what if you got 15 layers?

Dalen 2010-10-12 07:25:04

Well,what i intend to achieve is show the *smallest* (in terms on layer number) layer which is hidden. I don't see anything logically wrong with my code

Anant 2010-10-12 07:27:09

have you tried with some alerts here and there?

Dalen 2010-10-12 07:31:41

yes,but the statement if ($('#three').is(':visible')) { three = 1; } else { three = 0; if (one == 1 }doesn't seem to be working.Even though,layer "three" is hidden,the three=1; as per an alert

Anant 2010-10-12 07:36:14

without the HTML code it is hard to figure out the problem.

Dalen 2010-10-12 07:51:58

the main problem is that the if() statements aren't working. can i post the code somewhere ?

Anant 2010-10-12 07:54:21

just post it here if it is not that heavy

Dalen 2010-10-12 07:56:47

Anant 2010-10-12 07:58:51

try to use display:none instead of visibility:hidden

Dalen 2010-10-12 08:21:16

for me it works in this way: put your function into a <script> tag. after your function, into the same tag, put this line: $(document).ready(function(){setInterval('open()', 1000);}); this way alert(free) alway show 1 to me

Dalen 2010-10-12 08:32:23

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