Android Web service problem.

Question

Hi all.

i m calling an webservice which is soap based in my android application. it is returning me the XML response. how can i parse it?? i checked the xml parsing its asking for the URL. i m confused which url i need to pass??

Here is the code:

SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); request.addProperty("pStrType", type);

request.addProperty("pIntPageNo", PageNo)

request.addProperty("pIntPageSize", PageSize);

           //Log.v(LOG_TAG," value:="+name);

           //Log.v(LOG_TAG," value:="+pass);
           SoapSerializationEnvelope envelope = 
           new SoapSerializationEnvelope(SoapEnvelope.VER11);
           envelope.dotNet = true;
           envelope.setOutputSoapObject(request);
           AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(URL);
           try
           {
           androidHttpTransport.call(SOAP_ACTION, envelope);
           SoapObject resultstring = (SoapObject) envelope.bodyIn; 
           Log.v(LOG_TAG," value:="+resultstring);
           String Result=resultstring.toString();

What to do after dis?? m getting the string of response in (resultString)

pls pls help me its very urgent.

Answer 1

If you know how to use SAX XML Parser, you can convert the String into a byte stream and pass it to your handler.

    String result=resultstring.toString();
    SAXParser saxP = SAXParserFactory.newInstance().newSAXParser();
    ResponseHandler respH = new ResponseHandler();//your implementation
    saxP.parse(new ByteArrayInputStream(result.getBytes()), respH);            

If you don't know SAX parser, i would advice you to learn that first. It is simple.

Hope that helps.

Answer 2

You need to get some sort of Code generator like WSClient++