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37

answers:

1

Lets said I have the matrix M = ones(3); and I want to divide each row by a different number, e.g., C = [1;2;3];.

1 1 1  -divide_by-> 1      1   1   1
1 1 1  -divide_by-> 2  =  0.5 0.5 0.5
1 1 1  -divide_by-> 3     0.3 0.3 0.3

How can I do this without using loops?

+3  A: 

Use right array division as documented here

result = M./C

whereas C has the following form:

C = [ 1 1 1 ; 2 2 2 ; 3 3 3 ];

EDIT:

result = bsxfun(@rdivide, M, [1 2 3]'); % untested !
zellus
I went through that documentation before. Nevertheless, they explicitly said that both matrix should have the same dimension. Not this being the case.I also was thinking: is it possible to expand the vector to a matrix of the same size to perform element by element division?
adn
the first one is basically `M ./ repmat(C,1,3)`. An additional solution is: `M ./ (C*ones(1,3))`, though I prefer to use BSXFUN.
Amro

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