How to display all images from a WordPress post?

Question

I'm trying to get all images from a WP post to create a slideshow from them. Googled around and found this piece of code to retrieve and display images from a post:

function getImage($num) {
    global $more;
    $more = 1;
    $link = get_permalink();
    $content = get_the_content();
    $count = substr_count($content, '<img');
    $start = 0;
    for($i=1;$i<=$count;$i++) {
        $imgBeg = strpos($content, '<img', $start);
        $post = substr($content, $imgBeg);
        $imgEnd = strpos($post, '>');
        $postOutput = substr($post, 0, $imgEnd+1);
        $postOutput = preg_replace('/width="([0-9]*)" height="([0-9]*)"/', '',$postOutput);;
        $image[$i] = $postOutput;
        $start=$imgEnd+1;
    }
    if(stristr($image[$num],'<img')) { echo '<a href="'.$link.'">'.$image[$num]."</a>"; }
    $more = 0;
}

As you can imagine you then use getImage('1') etc. to get 1st, 2nd images from the post etc. This isn't ideal to create a slideshow, because I don't know how many image will there be.

Is there a way to modify the code above to get an array of images to use to create a foreach loop, for example? Sorry if my logic is a bit flawed, I'm not a PHP expert, as you might have guessed.

Thanks in advance for any help.

Answer 1

This code is already finding all the images, but is only printing out 1.

Try this variation, which should echo all images instead of just 1. I haven't tested this, but if you original code worked, this should.

function getImage() {
    global $more;
    $more = 1;
    $link = get_permalink();
    $content = get_the_content();
    $count = substr_count($content, '<img');
    $start = 0;
    for($i=1;$i<=$count;$i++) {
        $imgBeg = strpos($content, '<img', $start);
        $post = substr($content, $imgBeg);
        $imgEnd = strpos($post, '>');
        $postOutput = substr($post, 0, $imgEnd+1);
        $postOutput = preg_replace('/width="([0-9]*)" height="([0-9]*)"/', '',$postOutput);;
        if(stristr($postOutput,'<img')) { echo '<a href="'.$link.'">'.$postOutput."</a>"; }
        $start=$imgEnd+1;
    }
    $more = 0;
}

There is a lot more cleanup that could be done on this code as well, but I just modified what you had.