How can I send a file in django to a different server without user being redirected to the server ? So all goes to rewriting this simple php function in django :
$filename = 'C:/tmp/myphoto.jpg';
$handler = 'http://www.example.com/upload.php';
$field = 'image';
$res = send_file($filename, $handler, $field);
if ($res) {
echo 'done.';
} else {
echo 'something went wrong.';
}
Function on the second server is just simple php func that reads files from $_FILES:
<?php
move_uploaded_file(
$_FILES['image']['tmp_name'],
'/var/www/image/uploaded-file.jpg'
);
echo 'file saved.';
?>
I've already tried django-filetransfers, and it works but I somehow cannot make it stay on the page from which I am uploading file. I have edited the upload_handler view and files are sent properly but after that I'm redirected to my second server :
def upload_handler(request):
if request.method == 'POST':
form = UploadForm(request.POST, request.FILES)
if form.is_valid():
form.save()
return HttpResponseRedirect("/upload")
upload_url, upload_data = prepare_upload(request, "address of my server/")
form = UploadForm()
return direct_to_template(request, '/upload.html',
{'form': form, 'upload_url': upload_url, 'upload_data': upload_data,
'uploads': UploadModel.objects.all()})
And here's my approach. I'm using functions from httplib and also multipart_encode function from python-poster that creates me file headers :
def file_upload(request):
if request.method == 'POST':
form = UploadFileForm(request.POST, request.FILES)
if form.is_valid():
f = request.FILES['file']
logging.debug(f)
status = send_file(request.FILES['file'])
c = RequestContext(request, {
"status" : status,
})
template = "management/status.html"
result = render_to_string(template, c)
return HttpResponse(result)
else:
form = UploadFileForm()
return render_to_response('management/file_upload.html', {'form': form})
def send_file(file):
datagen, headers = multipart_encode({"myfile": file})
conn = httplib.HTTPConnection(HOST)
conn.request('POST', '/rte/', file, headers)
res = conn.getresponse()
if res.status != 200:
logging.debug("error \n")
logging.debug(file)
logging.debug("\n")
logging.debug(headers)
return res.status
HTML:
<form action="{{ views.file_upload }}" method="POST" enctype="multipart/form-data">
{{ form.as_p }}
<input type="submit" value="Upload" />
</form>
As a result I get 'Error 500' and in debug :
2010-10-20 18:12:55,819 DEBUG thumb.php4.jpg
2010-10-20 18:14:55,968 DEBUG error
2010-10-20 18:14:55,968 DEBUG thumb.php4.jpg
2010-10-20 18:14:55,969 DEBUG
2010-10-20 18:14:55,969 DEBUG {'Content-Length': 15019, 'Content-Type': 'multipart/form-data; boundary=02cafbc1d080471284be55dc1095b399'}
My functions are based on python/django docs and few solutions I've found on the internet. Functionality looks the same but somehow it doesn't work. Should I take different approach ? In php I do not need to define headers etc.