Pass more than one model to view

Question

public ActionResult Index()
{ 
    var pr = db.products;
    return View(pr); 
}

Firstly - I want to pass to the view more data - something like:

public ActionResult Index()
{ 
    var pr = db.products;
    var lr = db.linksforproducts(2)
    return View(pr,lr); 
}

How do I read the lr data in the view?

Secondly - on the view I have a table of products, and I want to add to the table a column with all the tags of this products. How do I get the tags for every product?

now i create this code

public class catnewModel
{

    public IQueryable<category> dl { get; set;   }
    public IQueryable<product> dr { get; set;   }
}

and my controller

public ActionResult Index()
    {

        var pr = db.products;
        var pl = db.categories;

        catnewModel model = new catnewModel();
        model.dr = pr;
        model.dl = pl;

        return View(model);
    }

in my view i try to iterate over

 <% foreach (var item in Model.dr)  %>

but i get error on

error CS1061: 'System.Collections.Generic.IEnumerable<amief.Models.catnewModel>' does not contain a definition for 'dr' and no extension method 

Answer 1

I have done this by making a ViewModel specific to the view you need the information in.

Then within that ViewModel just have properties to house your other models.

Something like this:

public class ViewModel
{
    public List<ProductModel> Products(){get; set;}
    public List<LinksForProductModel> LinksForProducts(){get; set;}
}


public ActionResult Index()
{ 
    var pr = db.products;
    var lr = db.linksforproducts(2)

    ViewModel model = new ViewModel();
    model.Products = pr;
    model.LinksForProducts = lr;


    return View(model); 
}

Answer 2

Usually - You create view model per view.

In Your case, that would be:

public class IndexModel{
  public ProductModel[] Products{get;set;}
  public LinkForProduct[] Links{get;set;}
}

public ActionResult Index(){
  var model=new IndexModel{
    Products=Map(db.products), 
    Links=Map(db.linksforproducts(2)};
  return View(model);
}

Answer 3

Create a view model containing two properties:

public class MyViewModel
{
    public IEnumerable<Product> Products { get; set; }
    public IEnumerable<LinkProduct> Links { get; set; }
}

And in your controller:

public ActionResult Index()
{ 
    var model = new MyViewModel
    {
        Products = db.products,
        Links = db.linksforproducts(2)
    };
    return View(model); 
}