change dd/mm/yy date format to yy/mm/dd using php

Question

I'm having date 20/12/2001 in this formate . i need to convert in following formate 2001/12/20 using php .

thanks in advance

Answer 1

$today = date("Y/m/d");

I believe that should work... Someone correct me if I am wrong.

Answer 2

$var = explode('/',$date);
$var = array_reverse($var);
$final = implode('/',$var);

Answer 3

If you're getting the date string from somewhere else (as opposed to generating it yourself) and need to reformat it:

$date = '20/12/2001';
preg_replace('!(\d+)/(\d+)/(\d+)!', '$3/$2/$1', $date);

If you need the date for other purposes and are running PHP >= 5.3.0:

$when = DateTime::createFromFormat('d/m/Y', $date);
$when->format('Y/m/d');
// $when can be used for all sorts of things

Answer 4

You will need to manually parse it.

1. Split/explode text on "/".
2. Check you have three elements.
3. Do other basic checks that you have day in [0], month in [1] and year in [2] (that mostly means checking they're numbers and int he correct range)
4. Put them together again.

Answer 5

Your safest bet

<?php
$input = '20/12/2001';
list($day, $month, $year) = explode('/',$input);
$output= "$year/$month/$day";
echo $output."\n";

Add validation as needed/desired. You input date isn't a known valid date format, so strToTime won't work.

Alternately, you could use mktime to create a date once you had the day, month, and year, and then use date to format it.

Answer 6

You can use sscanf in order to parse and reorder the parts of the date:

$theDate = '20/12/2001';
$newDate = join(sscanf($theDate, '%3$2s/%2$2s/%1$4s'), '/');

assert($newDate == '2001/12/20');

Or, if you are using PHP 5.3, you can use the DateTime object to do the converting:

$theDate = '20/12/2001';
$date = DateTime::createFromFormat('d/m/Y', $theDate);
$newDate = $date->format('Y/m/d');

assert($newDate == '2001/12/20');

Answer 7

$date = Date::CreateFromFormat('20/12/2001', 'd/m/Y');
$newdate = $date->format('Y/m/d');