Evaluate keyword density of a given block of text

Question

I would like to use php to pass a keyword phrase to a function and have the function parse a block of text and return the keyword density of the input phrase as a percentage of the total word count of the text block.

Answer 1

How about:

• Split the input text on spaces to get a array of words using preg_split.
• Use count function to get the total number of words.
• Use the array_count_values function to get the number of time the keyword appears.
• Calculate ratio of previous two computed values.

You'll have to filter the input text by removing punctuations before you split it.

Answer 2

Check out:

• PHP Keyword Density N-Gram Analysis Algorithm

Answer 3

Take a look at:

• http://www.bitrepository.com/word-popularity-script.html

Answer 4

$text = 'lorem ipsum etc';
$keyword = 'lorem ipsum';

$word_count = explode(' ', $text);
$word_count = count($word_count);

$keyword_count = preg_match_all("#{$keyword}#si", $text, $matches);
$keyword_count = count($matches);

$density = $keyword_count / $word_count * 100;

echo number_format($density, 2) . '%';