if all in list == something

Question

Using python 2.6 is there a way to check if all the items of a sequence equals a given value, in one statement?

[pseudocode]
my_sequence = (2,5,7,82,35)

if all the values in (type(i) for i in my_sequence) == int:
     do()

instead of, say:

my_sequence = (2,5,7,82,35)
all_int = True
for i in my_sequence:
    if type(i) is not int:
        all_int = False
        break

if all_int:
    do()

Answer 1

Do you mean

all( type(i) is int for i in my_list )

?

Edit: Changed to is. Slightly faster.

Answer 2

how about:

all( type(i) is int for i in lst )

example:

In [1]: lst = range(10)
In [2]: all( type(i) is int for i in lst )
Out[2]: True
In [3]: lst.append('steve')
In [4]: all( type(i) is int for i in lst )
Out[4]: False

[edit] made cleaner as per comments

Answer 3

I would suggest:

if all(isinstance(i, int) for i in my_list):

all and any first appeared in Python 2.5. If you're using an older version of Python, the links provide sample implementations.

I also suggest using isinstance since it will also catch subclasses of int.