submit a form via Ajax using prototype and update a result div

Question

Hello, I'm wondering how can I submit a form via Ajax (using prototype framework) and display the server response in a "result" div. The html looks like this :

<form id="myForm" action="/getResults">
    [...]
    <input type="submit" value="submit" />
</form>
<div id="result"></div>

I tried to attach a javascript function (which uses Ajax.Updater) to "onsubmit" (on the form) and "onclick" (on the input) but the form is still "non-Ajax" submitted after the function ends (so the whole page is replaced by the results).

Answer 1

You need to return the value false from the ajax function, which blocks the standard form submit.

<form id="myForm" onsubmit="return myfunc()" action="/getResults">


function myfunc(){
   ... do prototype ajax stuff...
  return false;

}

Using onsubmit on the form also captures users who submit with the enter key.

Answer 2

You first need to serialize your form, then call an Ajax Updater, using POST options and pass it the serialized form data. The result will then appear in the element you sepcified.

Answer 3

Check out Prototype API's pages on Form.Request and Event handling.

Basically, if you have this:

<form id='myForm'>
.... fields ....
<input type='submit' value='Go'>
</form>
<div id='result'></div>

Your js would be, more or less:

Event.observe('myForm', 'submit', function(event) {
    $('myForm').request({
        onFailure: function() { .... },
        onSuccess: function(t) {
            $('result').update(t.responseText);
        }
    });
    Event.stop(event); // stop the form from submitting
});