I have this list
["[email protected] : martin00", ""],
How do i split so it only be left
[email protected]:martin00
views:
856answers:
6
+3
A:
Do you want to have: aList[0] ?
EDIT::
Oh, you have a tuple with the list in it!
Now I see:
al = ["[email protected] : martin00", ""],
#type(al) == tuple
#len(al) == 1
aList = al[0]
#type(aList) == list
#len(aList) == 2
#Now you can type:
aList[0]
#and you get:
"[email protected] : martin00"
You can use aList[0].replace(' : ', ':') if you wish to remove spaces before and after colon, suit your needs.
I think that the most confusing thing here is the coma ending the first line. It creates a new tuple, that contains your list.
Abgan
2009-01-29 16:51:45
+1
A:
Exactly.
$ python
Python 2.6 (r26:66714, Dec 4 2008, 11:34:15)
[GCC 4.0.1 (Apple Inc. build 5488)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> al = ["[email protected] : martin00", ""]
>>> print al[0]
[email protected] : martin00
>>>
Charlie Martin
2009-01-29 16:53:49
A:
Abgan, is probably correct, although if you still want a list, ie.,
["[email protected] : martin00"]
you'd want:
the_list[:1]
Dana
2009-01-29 16:54:02
The question suprised me so much, that I posted only the most obvious answer. I'm beginning to doubt if there is really no too newbie questions ;-)
Abgan
2009-01-29 16:55:20
I was not correct. He was creating a tuple with a list inside, so he needed to do al[0][0] to retrieve the actual string. See the comma ending the first line of his code?
Abgan
2009-01-29 17:19:10
I see it now. It didn't click that it was indicated a tuple, I just figured it was part of his sentence structure :P
Dana
2009-01-29 17:40:25
A:
lists can be accessed by index or sliced into smaller lists.
http://diveintopython.org/native_data_types/lists.html#d0e5623
Yoni Samlan
2009-01-29 16:54:16
+2
A:
comma at the end means that list is first member of a tuple, but to your question:
in_list = ["[email protected] : martin00", ""]
result = ''.join(in_list[0].split(' '))
SilentGhost
2009-01-29 16:56:37
+3
A:
al = ["[email protected] : martin00", ""],
print al[0][0].replace(" : ", ":")
Ionuț G. Stan
2009-01-29 17:03:32