How to *printf* in Python?

Question

The question is in the title.

I'd like to do in Python what I do in this example in C:

#include <stdio.h>

int main() {
    int i;
    for (i=0; i<10; i++) printf(".");
    return 0;
}

Output:

..........

In Python:

>>> for i in xrange(0,10): print '.'
.
.
.
.
.
.
.
.
.
.
>>> for i in xrange(0,10): print '.',
. . . . . . . . . .

In Python print will add a '\n' or a space, how can I avoid that? Now, it's just an example. Don't tell me I can first make a string then print it. I'd like to know how to "append" strings to the stdout (I don't know if it's worded correctly).

---

I know about the comma, did you read my Python example?!?

Answer 1

import sys
sys.stdout.write('.')

or

print('.'), # this will still print a space, but not a newline

Answer 2

Try adding a comma:

print "Hi",
print "There"

Check here for more details: http://blog.code-head.com/print-without-a-new-line-or-space-in-python

Answer 3

The new (as of Python 3.0) print function has an optional end parameter that let's you modify the ending character. There's also sep for separator.

Answer 4

Since people may come here looking for it based on the title, Python also supports printf-style substitution:

>>> strings = [ "one", "two", "three" ]
>>>
>>> for i in xrange(3):
...     print "Item %d: %s" % (i, strings[i])
...
Item 0: one
Item 1: two
Item 2: three

And, you can handily multiply string values:

>>> print "." * 10
..........

Answer 5

Print without a space or newline:

print "text" + "\r",