HOWTO: XML-RPC dynamic function registration in python?

Question

I am new to XML-RPC.

#client code
import xmlrpclib
proxy = xmlrpclib.ServerProxy("http://localhost:8000/")
x,y = arg1,arg2
print proxy.fun1(x,y)
print proxy.fun2(x,y)

What server should do:

1. load fun1
2. register fun1
3. return result
4. unload fun1

and then do same with fun2.

What is the best way to do this?

I have figured out a way to do this but it sounds "clumsy,far fetched and unpythonic".

Answer 1

Generally the server keeps on running - so register both methods at the start. I don't understand why you want to unregister your functions. Servers stay up and handle multiple requests. You might possible want a shutdown() function that shuts the entire server down, but I don't see anyway to unregister a single function.

The easiest way is with SimpleXMLRPCServer:

from SimpleXMLRPCServer import SimpleXMLRPCServer

def fun1(x, y):
    return x + y


def fun2(x, y):
    return x - y

server = SimpleXMLRPCServer(("localhost", 8000))
server.register_function(fun1)
server.register_function(fun2)
server.serve_forever()

Answer 2

If you want dynamic registering, register an instance of an object, and then set attributes on that object. You can get more advanced by using the __getattr__ method of the class if the function needs to be determined at run time.

class dispatcher(object): pass
   def __getattr__(self, name):
     # logic to determine if 'name' is a function, and what
     # function should be returned
     return the_func
server = SimpleXMLRPCServer(("localhost", 8000))
server.register_instance(dispatcher())