I am trying to create a simple Python extension using [PyCXX]. And I'm compiling against my Python 2.5 installation.
My goal is to be able to do the following in Python:
import Cats
kitty = Cats.Kitty()
if type(kitty) == Cats.Kitty:
kitty.Speak()
But every time I try, this is the error that I get:
TypeError: cannot create 'Kitty' instances
It does see Cats.Kitty
as a type object, but I can't create instances of the Kitty class, any ideas?
Here is my current source:
#include "CXX/Objects.hxx"
#include "CXX/Extensions.hxx"
#include <iostream>
using namespace Py;
using namespace std;
class Kitty : public Py::PythonExtension<Kitty>
{
public:
Kitty()
{
}
virtual ~Kitty()
{
}
static void init_type(void)
{
behaviors().name("Kitty");
behaviors().supportGetattr();
add_varargs_method("Speak", &Kitty::Speak);
}
virtual Py::Object getattr( const char *name )
{
return getattr_methods( name );
}
Py::Object Speak( const Py::Tuple &args )
{
cout << "Meow!" << endl;
return Py::None();
}
};
class Cats : public ExtensionModule<Cats>
{
public:
Cats()
: ExtensionModule<Cats>("Cats")
{
Kitty::init_type();
initialize();
Dict d(moduleDictionary());
d["Kitty"] = Type((PyObject*)Kitty::type_object());
}
virtual ~Cats()
{
}
Py::Object factory_Kitty( const Py::Tuple &rargs )
{
return Py::asObject( new Kitty );
}
};
void init_Cats()
{
static Cats* cats = new Cats;
}
int main(int argc, char* argv[])
{
Py_Initialize();
init_Cats();
return Py_Main(argc, argv);
return 0;
}