You can do this with VBA:
Public Function XOR_binary(b1, b2) As String
Dim len_b1
Dim len_b2
Dim len_diff
Dim i
Dim bit1
Dim bit2
' see if the two string are the same length. If not, add 0's to
' the beginning of the shorter string
len_b1 = Len(b1)
len_b2 = Len(b2)
len_diff = len_b1 - len_b2
Select Case len_diff
Case Is < 0
' b2 is longer
b1 = String(Abs(len_diff), "0") & b1
Case Is = 0
' they're the same length
Case Is > 0
' b1 is longer
b2 = String(len_diff, "0") & b2
End Select
XOR_binary = ""
For i = Len(b2) To 1 Step -1
bit1 = CInt(Mid(b1, i, 1))
bit2 = CInt(Mid(b2, i, 1))
XOR_binary = CInt(bit1 Xor bit2) & XOR_binary
Next i
End Function
Probably not the best implementation, but it works.
Using your example, A3
contains:
=XOR_Binary(A1,A2)
The resulting string will have the same number of bits as the longest string you pass in.