for (i = 0; i < document.checks.user.length; i++) //for all check boxes
{
if (document.checks.user[i].checked == true )
{
document.checks.submit();
return 0;
}
}
<body>
<form action="" method=POST name="checks" ID="Form2">
I have a bike:
<input type="checkbox" name="user" value="Bike" ID="Checkbox1">
<br>
<br>
</form>
<input type="button" value="Delete"
class="btn" onclick="sub_delete()"
onmouseover="hov(this, 'btn btnhov')" onmouseout="hov(this, 'btn')"
id="Button1" name="Button1"
/>
</body>
as you probably already know when there is only one check box left document.checks.user.length = undefined. Whats the most efficient way to make sure that when there is only one check box, it will be deleted. I was thinking just thinking to add it as a seperate if statement before the if statement here.....any suggesstions.
Thanks.