how to convert hex to byte for the following program?

Question

public static String asHex (byte buf[]) {
    StringBuffer strbuf = new StringBuffer(buf.length * 2);
    int i;

    for (i = 0; i < buf.length; i++) {
        if (((int) buf[i] & 0xff) < 0x10)
            strbuf.append("0");

        strbuf.append(Long.toString((int) buf[i] & 0xff, 16));
    }

    return strbuf.toString();
}

Answer 1

To get a hexadecimal string representation of a byte array, you could use String.format() with the %X format specifier:

public static String asHex(byte buf[]) 
{
    StringBuffer strbuf = new StringBuffer(buf.length * 2);

    for (byte b : buf)
       strbuf.append(String.format("%02X", b));

    return strbuf.toString();
}

The following method gives the inverse operation, returning a byte array representation of a hexadecimal string. It uses Byte.parseByte() and some bit shifting to get two characters in one byte:

public static byte[] asBytes(String str)
{
    if ((str.length() % 2) == 1) str = "0" + str; // pad leading 0 if needed
    byte[] buf = new byte[str.length() / 2];
    int i = 0;

    for (char c : str.toCharArray())
    {
        byte b = Byte.parseByte(String.valueOf(c), 16);
        buf[i/2] |= (b << (((i % 2) == 0) ? 4 : 0));
        i++;
    }

    return buf;
}

Answer 2

Here's a complete program which includes the asBytes() function which is what I assume you were looking for, the opposite to asHex():

public class Temp {
    public static String asHex (byte buf[]) {
        StringBuffer strbuf = new StringBuffer(buf.length * 2);
        int i;
        for (i = 0; i < buf.length; i++) {
            if (((int) buf[i] & 0xff) < 0x10)
                strbuf.append("0");
            strbuf.append(Long.toString((int) buf[i] & 0xff, 16));
        }
       return strbuf.toString();
    }
    public static byte[] asBytes (String s) {
        String s2;
        byte[] b = new byte[s.length() / 2];
        int i;
        for (i = 0; i < s.length() / 2; i++) {
            s2 = s.substring(i * 2, i * 2 + 2);
            b[i] = (byte)(Integer.parseInt(s2, 16) & 0xff);
        }
        return b;
    }
    static public void main(String args[]) {
        byte[] b = Temp.asBytes("010203040506070809fdfeff");
        String s = Temp.asHex(b);
        System.out.println (s);
    }
}

Answer 3

can anyone explain me the program which is written as

public static String asHex (byte buf[]) { StringBuffer strbuf = new StringBuffer(buf.length * 2); int i;

for (i = 0; i < buf.length; i++) {
    if (((int) buf[i] & 0xff) < 0x10)
        strbuf.append("0");

    strbuf.append(Long.toString((int) buf[i] & 0xff, 16));
}

return strbuf.toString();

}

Answer 4

Check here for couple of good methods to do this.

Answer 5

i need the explanation of the above code.urgent.please