Android- how can I convert android.net.Uri object to java.net.URI object?

Question

Thanks for any help.

I am trying to get a FileInputStream object on an image that the user selects from the picture gallery. This is the android URI returned by android.provider.MediaStore.Images.Media.INTERNAL_CONTENT_URI

content://media/external/images/media/3

When I try to construct a java URI object from this object, I get an IllegalArgumentException with the exception description Expected file scheme in URI: content://media/external/images/media/3 whereas the android URI shows the scheme as content

Never found a solution for the original question. But if you want the byte stream of an image in the pictures gallery, this piece of code will do that.

Bitmap bitmap = Media.getBitmap(getContentResolver(), imageUri);
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.JPEG, 40, bytes);
ByteArrayInputStream fileInputStream = new ByteArrayInputStream(bytes.toByteArray());

Answer 1

You could use the toString method of the android URI in combination of the String based constructor of the java URI

 android.net.URI auri = new android.net.URI(what ever);
 java.net.URI juri = new java.net.URI(auri.toString());

Android URI | Java URI

Answer 2

Since the String constructing doesn't work have you tried just constructing it your self?

android.net.URI auri = new android.net.URI(what ever);
java.net.URI juri = new java.net.URI(auri.getSchema(),
                                     auri.getSchemaSpecificPart(),
                                     auri.getFragment());

You might also want to double check that your getting valid data out of Android URI class. The docs as listed in my other answer discuss how it does pretty much no error checking. If there is infact an error the class just spits out garbage anyway and doesn't throw any exceptions. Which could very likely be why the java class which does do validation is throwing an exception.

Answer 3

Hi, i am having the same problem as discussed above:

FileInputStream (content://media/external/images/media/6);

file not found exception

any solution?

Answer 4

Found the correct way to open InputStream from content URI:

InputStream fileInputStream=yourContext.getContentResolver().openInputStream(uri);

That's all!