sed scripting - environment variable substitution

Question

Hi all,

I have sed related question:

If I run these command from a scrip:

#my.sh
PWD=bla
sed 's/xxx/'$PWD'/'
...
$ ./my.sh
xxx
bla

Which is fine.

But, if i run:

#my.sh
sed 's/xxx/'$PWD'/'
...
$ ./my.sh
$ sed: -e expression #1, char 8: Unknown option to `s'

I read in tutorials that to substitute env. variables from shell you need to stop, and 'out quote' the $varname part so that it is not substituted directly, which is what I did, and which works only if the variable is defined immediately before.

How can I get sed to recognize a $var as a env. variable as it is defined in the shell ?

Answer 1

With your question edit, I see your problem. Let's say the current directory is /home/yourname ... in this case, your command below:

sed 's/xxx/'$PWD'/'

will be expanded to

sed `s/xxx//home/yourname//

which is not valid. You need to put a \ character in front of each / in your $PWD if you want to do this.

Answer 2

Your two examples look identical, whcih makes problems hard to diagnose. Potential problems:

1. You may need double quotes, as in sed 's/xxx/'"$PWD"'/'

2. $PWD may contain a slash, in which case you need to find a character not contained in $PWD to use as a delimiter.

Answer 3

In addition to Norman Ramsey's answer, I'd like to add that you can double-quote the entire string (which may make the statement more readable and less error prone).

So if you want to search for 'foo' and replace it with the content of $BAR, you can enclose the sed command in double-quotes.

sed 's/foo/$BAR/g'
sed "s/foo/$BAR/g"

In the first, $BAR will not expand correctly while in the second $BAR will expand correctly.