I've been struggling with doing some relatively straightforward regular expression matching in Java 1.4.2. I'm much more comfortable with the Perl way of doing things. Here's what's going on:
I am attempting to match /^<foo>/ from "<foo><bar>"
I try:
Pattern myPattern= Pattern.compile("^<foo>");
Matcher myMatcher= myPattern.matcher("<foo><bar>");
System.out.println(myMatcher.matches());
And I get "false"
I am used to saying:
print "<foo><bar>" =~ /^<foo>/;
which does indeed return true.
After much searching and experimentation, I discovered this which said:
"The String method further optimizes its search criteria by placing an invisible ^ before the pattern and a $ after it."
When I tried:
Pattern myPattern= Pattern.compile("^<foo>.*");
Matcher myMatcher= myPattern.matcher("<foo><bar>");
System.out.println(myMatcher.matches());
then it returns the expected true. I do not want that pattern though. The terminating .* should not be necessary.
Then I discovered the Matcher.useAnchoringBounds(boolean) method. I thought that expressly telling it to not use the anchoring bounds would work. It did not. I tried issuing a
myMatcher.reset();
in case I needed to flush it after turning the attribute off. No luck. Subsequently calling .matches() still returns false.
What have I overlooked?
Edit: Well, that was easy, thanks.