In C#. I have a double (which I've extracted from a database) that has 20 digit precision. In Visual Studio (using QuickWatch) I can see the value of the double to be = 0.00034101243963859839.
I want to display this value in a textbox and then have it be the same value when I take it out and convert it back into a double. But I always lose the last two digits
I've tried the following:
double d = 0.00034101243963859839;
string s = d.ToString();
string s2 = d.ToString("F20");
string s3 = d.ToString("0.00000000000000000000"); -- 20 0's
string s4 = (d*100d).ToString();
In these cases:
s = 0.000341012439638598 s2 = 0.00034101243963859800 s3 = 0.00034101243963859800 s4 = 0.0341012439638598
I want to be able to do the following:
double d = 0.00034101243963859839;
string s = d.ToString();
//...
double d2 = double.Parse(s);
if(d == d2)
{
//-- Success
}
Is there any way to keep those last two digits of precision??