How to find whether a number belongs to a particular range in Python ?

Question

Suppose i want to check 1.1 belongs to range 0 to 0.5 how can i do it?

with range i can do :

for i in range(0,0.5):
  if i == 1.1:
    print 'yes'
  if i != 1.1:
    print 'no'

Is ther any other way to do this ????

Answer 1

print 'yes' if 0 < x < 0.5 else 'no'

range() is for generating arrays of consecutive integers

Answer 2

No, you can't do that. range() expects integer arguments. If you want to know if x is inside this range try some form of this:

print 0.0 <= x <= 0.5

Be careful with your upper limit. If you use range() it is excluded (range(0, 5) does not include 5!)

Answer 3

>>> s = 1.1
>>> 0<= s <=0.2
False
>>> 0<= s <=1.2
True

Answer 4

def belongsTo(value, rangeStart, rangeEnd):
        if value >= rangeStart and value <= rangeEnd:
                return True
        return False

Now you can:

print "1.1 belongs to <0, 0.5>:", belongsTo(1.1, 0, 0.5)

Answer 5

To check whether some number n is in the inclusive range denoted by the two number a and b you do either

if   a <= n <= b:
    print "yes"
else:
    print "no"

use the replace '>=' and '<=' withe '>' and '<' to check whether n is in the exclusive range denoted by a and b (i.e. a and b are not themselves members of the range)

Alternatively, you can also check for

if (b - n) >= a :
    print "yes"
    ...

Range will produce an arithmetic progression defined by the two (or three) arguments converted to integers. See the documentation. This is not what you want I guess.

Answer 6

Old faithful:

if n >= a and n <= b:

And it doesn't look like Perl (joke)

Answer 7

I would use the numpy library, which would allow you to do this for a list of numbers as well:

from numpy import array
a = array([1, 2, 3, 4, 5, 6,])
a[a < 2]