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Python regex split a string by one of two delimiters

Answer 1

+8 A:

Doh!

It's just this.

sep = re.compile('[\s,]+')

interstar 2009-03-06 11:42:11

In Perl (probably in Python, due to the fact that it appears to be doing the same thing) using ()s in a regex when splitting causes the split() to preserve the match (between the parens), and return a list with the pattern match in between the items you want. So maybe don't use ()s in a split.

Chris Lutz 2009-03-06 22:56:56

Answer 2

A:

I like the following...

>>> sep= re.compile( r',*\s*' )
>>> sep.split("""[email protected], [email protected]

   [email protected],,[email protected]""")
['[email protected]', '[email protected]', '[email protected]', '[email protected]']

Which also seems to work on your test data.

S.Lott 2009-03-06 11:44:11

+1: I don't know why this was down voted before, but it works quite nicely.

tgray 2009-03-06 20:35:24

That regex will match the empty string, since it uses star quantifiers for everything. Really you want to split on at least one character; the OP's solution with a character class and plus quantifier is better, not to mention much clearer to read.

kquinn 2009-03-06 23:07:17

I see. I don't think regular expressions can be ranked on readability, but I get your point about matching at least one character.

tgray 2009-03-09 12:52:30

Answer 3

+2 A:

without re

line = 'e@d , f@g, 7@g'

addresses = line.split(',')    
addresses = [ address.strip() for address in addresses ]

Mykola Golubyev 2009-03-06 12:23:44

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Python regex split a string by one of two delimiters

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