Strategy for detecting an object in JTable row?

Question

Here's the thing: a sortable JTable backed by JTableModel with an array of objects that populate rows (one object = one row). Need to delete rows.

Without sorting, deleting an object is simple: get selected row index, delete array object under the same index. With sorting, though, row indexes mess up in a sense that they no longer match backing array object indexes. What's the proper way to overcome this?

Answer 1

I think ( not quite sure ) there is a method like "modelToView" which returns the actual index in the model a view index represents.

So, for instance you have A,B,C,D and then you sort desc. D,C,B,A this method would return 0 for view index 3 ( A )

I think this was on JXTable which supports sorting or in JTable in Java 6.

If you have build this sorting your self, consider adding this method.

Answer 2

Oscar was almost right, here's how it should be done:

int selectedRow = table.getSelectedRow();
tableModel.removeRow(table.convertRowIndexToModel(selectedRow));