Hello,
Does anyone knows what magic I have to use to change x list:
x = [1,2,3,4,5,11]
into y list?
y = ['01','02','03','04','05','11']
Thank you all in advance for helping me...
views:
649answers:
6
+6
A:
You want to use the built-in map function:
>>> x = [1,2,3,4,5]
>>> x
[1, 2, 3, 4, 5]
>>> y = map(str, x)
>>> y
['1', '2', '3', '4', '5']
EDIT You changed the requirements on me! To make it display leading zeros, you do this:
>>> x = [1,2,3,4,5,11]
>>> y = ["%02d" % v for v in x]
>>> y
['01', '02', '03', '04', '05', '11']
Paolo Bergantino
2009-03-13 17:42:44
that semi-colon is staring at me! stop it!
jcoon
2009-03-13 17:44:56
Whooops! Old habits die hard.
Paolo Bergantino
2009-03-13 17:45:24
And if I'd like to add zero if the number is one digit and I want my numbers to be 2 digit each?
2009-03-13 17:48:46
I updated my answer to show how to display the leading zero.
Paolo Bergantino
2009-03-13 17:51:23
Thank you Paolo!
2009-03-13 17:54:46
+15
A:
You can use a list comprehension (Python 2.6+):
y = ["{0:0>2}".format(v) for v in x]
Or for Python prior to 2.6:
y = ["%02d" % v for v in x]
Edit: Missed the fact that you wanted zero-padding...
DNS
2009-03-13 17:45:20
Interesting, I haven't heard of this "{0:0>2}" syntax. Is it covered on any PEP or other document?
Rodrigo
2009-03-13 17:52:56
It's a new syntax that's (supposedly) meant to gradually replace % syntax. It's actually very nice for some things, and I've made a point of using it in my code, but it still looks weird to me after so long using %. More info here: http://docs.python.org/library/string.html#formatstrings
DNS
2009-03-13 18:00:37
+2
A:
I would use a list comprehension myself, but here is another solution using map for those interested...
map(lambda v: "%02d" %v, x)
Brian R. Bondy
2009-03-13 17:51:19
A:
An alternative to format strings would be to use the string's zfill() method:
y = [str(i).zfill(2) for i in x]
Another thing: you might be after padding based on the largest item in the list, so instead of just using 2, you could do:
pad_length = len(str(max(x)))
y = [str(i).zfill(pad_length) for i in x]