Alright, so I was taking a look at some source when I came across this:
>>> def __parse(self, filename):
... "parse ID3v1.0 tags from MP3 file"
... self.clear()
... try:
... fsock = open(filename, "rb", 0)
... try:
... fsock.seek(-128, 2)
... tagdata = fsock.read(128)
... finally:
... fsock.close()
... if tagdata[:3] == 'TAG':
... for tag, (start, end, parseFunc) in self.tagDataMap.items():
... self[tag] = parseFunc(tagdata[start:end])
... except IOError:
... pass
...
So, I decided to test it out.
>>> __parse("blah.mp3")
And, I received this error:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: __parse() takes exactly 2 arguments (1 given)
This wouldn't be the first time I've encountered this, I keep thinking I'm meant to include self in the argument parameter list, but I know that that's not right. Could someone explain to me why this happens a lot with code I try to play around with, I suppose its due to my level of understanding about the terms, I barely even understand what init or self does, or why it's relevant. def x(b): print b is the same as def x(self, b): self.b = b print self.b isn't it? Why does it matter so much!
I just want a basic explanation, so I can get this out of my mind,thanks.