How to get the filename without the extension from a path in Python?

Question

How to get the filename without the extension from a path in Python?

I found out a method called os.path.basename to get the filename with extension. But even when I import os, I am not able to call it path.basename. Is it possible to call it as directly as basename?

Answer 1

Getting the name of the file without the extension :

import os
print os.path.splitext("path_to_file")[0]

As for your import problem, you solve it this way :

from os.path import basename

# now you can call it directly with basename
print basename("/a/b/c.txt")

Answer 2

But even when I import os, I am not able to call it path.basename. Is it possible to call it as directly as basename?

import os, and then use os.path.basename

importing os doesn't mean you can use os.foo without referring to os.

Answer 3

Just roll it:

>>> base=os.path.basename('/root/dir/sub/file.ext')
>>> base
'file.ext'
>>> os.path.splitext(base)
('file', '.ext')
>>> os.path.splitext(base)[0]
'file'
>>>

Answer 4

>>> print os.path.splitext(os.path.basename("hemanth.txt"))[0]
hemanth

Answer 5

i want to extract rasmi.tar.gz to rasmi can anyone provime me the solution