That's because operator overloading is something they specifically left out of the language deliberately. They "cheated" a bit with string concatenation, but beyond that, such functionality doesn't exist.
(disclaimer: I haven't worked with the last 2 major releases of java, so if it's in now, I'll be very surprised)
Java does have a logical XOR operator, it is ^ (as in a ^ b).
Apart from that, you can't define new operators in Java.
Edit: Here's an example:
public static void main(String[] args) {
boolean[] all = { false, true };
for (boolean a : all) {
for (boolean b: all) {
boolean c = a ^ b;
System.out.println(a + " ^ " + b + " = " + c);
}
}
}
Output:
false ^ false = false false ^ true = true true ^ false = true true ^ true = false
The only operator overloading in Java is + on Strings (JLS 15.18.1 String Concatenation Operator +).
The community has been divided in 3 for years, 1/3 doesn't want it, 1/3 want it, and 1/3 doesn't care.
You can use unicode to create method names that are symbols... so if you have a symbol you want to use you could do myVal = x.$(y); where $ is the symbol and x is not a primitive... but that is going to be dodgy in some editors and is limiting since you cannot do it on a primitive.
Java has a logical AND operator.
Java has a logical OR operator.
Wrong.
Java has
XOR exists only as ^, because short-circuit evaluation is not possible.
Perhaps you misunderstood the difference between & and &&, | and || The purpose of the short cut operators && and || is that the value of the first operand can determine the result and so the second operand doesn't need to be evaluated.
This is especially useful if the second operand would results in an error. e.g.
if (set == null || set.isEmpty())
// or
if (list != null && list.size() > 0)
However with XOR, you always have to evaluate the second operand to get the result so the only meaningful operation is ^