How to find where Apache's httpd.exe is installed?

Question

How do I best figure out if and where Apache is installed on a windows machine?

I'm writing a script that uses the installed apache, but sets up it's own config & server-root, and I don't want to hardcode it nor have the user explicitly set it (unless necessary).

I tried to search the registry, but couldn't find anything useful.

Update for those posting default paths:

On my machine, it was in C:/Program Files/Apache Software Foundation/Apache2.2. And if I had Vista 64-bit, it'd probably be under 'Program Files (x86)'. And if the computer doesn't have an English OS, it's even worse.

Workaround:

Guess I have to check %PROGRAMFILES% for Apache 2.0 or 2.2's default path, then fall back to a prompt. It's be nice to read the registry and find out exactly where it is.

I can't really beleive I'm the first one who wants to solve this properly? :)

Answer 1

http://stackoverflow.com/questions/304319/is-there-an-equivalent-of-which-on-windows

Answer 2

On Windows it is installed in c:/Program Files/Apache Group/Apache2/bin/Apache.exe

Rest of the directories (conf, log, doc-root, etc) are under c:/Program Files/Apache Group/Apache2

Answer 3

Not really an answer, but if I were you, I'd only use the default path (%PROGRAMFILES%\Apache Group\Apache2\bin\Apache.exe) or a couple of relatively safe default paths, and prompt if the executable was not found.

Otherwise it might pick up a completely unexpected installation. I hate programs that are "too smart".

Answer 4

I hadn't installed Apache for all users on my machine, hence no registry key. But if one does that, it's located here:

HKEY_LOCAL_MACHINE\SOFTWARE\Apache Software Foundation\Apache\2.2.xx\ServerRoot