how to catch error in JQuery's load() method

Question

Hi all

i'm using Jquery's load() method for reterive some data when user click on button. Then show the result in . It is ok.

But the problem is i don't know how to catch error in load() when error occure while data reteriving.

Please help me.

Thanks

Answer 1

load() offers a callback.

Callback.
The function called when the ajax request is complete (not necessarily success).

This is how its done IIRC. (haven't tested it)

$("#feeds").load("feeds.php", {limit: 25}, 
    function (responseText, textStatus, XMLHttpRequest) {
        // XMLHttpRequest.responseText has the error info you want.
        alert(XMLHttpRequest.responseText);
});

Answer 2

Besides passing a callback to the load() function as Ólafur Waage suggests, you can also register "global" error handlers (global as in global for all ajax calls on the page).

There are at least two ways to register global Ajax error handlers :

Register just the error handler with ajaxError():

$.ajaxError(function(event, request, settings) {
      alert("Oops!!");
});

Or, use ajaxSetup() to set up an error handler and other properties at the same time:

$.ajaxSetup({
    timeout: 5000,
    error: function(event, request, settings){
        alert("Oops!");
    }
});

Answer 3

load() documentation.

Just a little background on how a load error happens...

$("body").load("/someotherpath/feedsx.pxhp", {limit: 25}, 
    function (responseText, textStatus, req) {
        if (textStatus == "error") {
          return "oh noes!!!!";
        }
});

Edit: Added a path other than the root path as requested by comments.

Answer 4

Electric toolbox has an article called "Loading content with jQuery AJAX and dealing with failures" that appears to answer your question.

Apparently the callback function that you specify gets passed the response, status, and XmlHttpRequest object, allowing you to determine the status of your ajax request and handle the condition accordingly.