What is the fastest way to reverse a comma-separated list in vim?

Question

I frequently must correct the following rails code:

assert_equal value, expected

The two arguments to assert_equal are out of order, and should read:

assert_equal expected, value

In vim, what is the most efficient way of going from the first line to the second?

Answer 1

Hum... I would say "tdwxx$i, ^["tp but that's not really efficient or easy, just quick enough to type...

Answer 2

Map a key combination to perform the command:

:s/^assert_equal \(.*\), \(.*\)$/assert_equal \2, \1

Answer 3

Via regex:

:s/\v([^, ]+)(\s*,\s*)([^, ]+)/\3\2\1/

If you do it often you can make a map out of it, e.g.:

:nmap <F5> :s/\v([^, ]+)(\s*,\s*)([^, ]+)/\3\2\1/<CR>

Put the cursor on the line you want to flip and hit F5.

Answer 4

This one swaps the word your cursor is on with the next one - just press F9 in command mode:

:map <F9> "qdiwdwep"qp

• "qdiw: Put the word your cursor is on into buffer 'q'
• dw: Delete all chars to the beginning of the next word (possibly comma + space)
• e: Go to end of word
• p: Paste (comma + space)
• "qp: Paste buffer 'q' (the first word)

Answer 5

I've always liked regular expression search and replace for these type of tasks:

:s/\(\w*\), \(\w*\)/\2, \1/

Will swap the first word with second in a comma separated list.

Answer 6

for something this simple, i would just make a little macro

qadf ea, ^[pxxq

then @a away