getting a long list from grep -l -- is it possible?

Question

I'm performing this grep: grep -l "Validation failed" *.dbg

This returns a file listing. However, I'm most interested in the times modified of these files.

What would the proper command be?

Edit: the argument in the title was wrong.

Answer 1

xargs is my friend, apparently. The answer is: grep -l "Validation failed" *.dbg | xargs ls -ltr

Answer 2

You can also do it with

for file in `grep -l "Validation failed" *.dbg`; do ls -ltr $file; done

but xargs is definitely neater, shorter, and gives you easy delimiter options.