Grep : get all file that doesn't have a line that matches

Question

This may be a duplicate as I believe I already saw something like that but can't find it anymore so I'm asking :

I have a lots of files with multiple lines, and in most case, one of the line contain a certain patern. I would like to have every file that do not have a line with this patern.

EDIT : Just need to use the "-L" grep option. This is a duplicate, I'm sure but don't find the original back ...

Answer 1

Grep returns 0/1 to indicate if there was a match, so you can do something like this:

for f in *.txt; do
    if ! grep -q "some expression" $f; then
        echo $f
    fi
done

EDIT: You can also use the -L option:

grep -L "some expression" *

Answer 2

Use the -v option. Man page excerpt:

-v, --invert-match
    Invert the sense of matching, to select non-matching lines.  (-v is specified by POSIX.)

As always, use man

Edit: No need to use for loops, just use the wildcard char:

grep -v "some expression" *

Answer 3

The answer was just to get the "-L" option in order to have file WITHOUT the pattern ... Should have read the man more carrefully!

Answer 4

try "count" and filter where equals ":0":

grep -c [pattern] * | grep ":0"

(if you use TurboGREP cough, you won't have a -L switch ;))