I've got a situation where I want to get a regexp from the user and run it against a few thousand input strings. In the manual I found that the RegExp
object has a .compile()
method which is used to speed things up ins such cases. But why do I have to pass the regexp string to it again if I already passed them in the constructor? Perhaps constructor does the compile()
itself?
views:
859answers:
2
+21
A:
The RegExp().compile() method is deprecated. It's basically the same as the constructor, which I assume is why it was deprecated. You should only have to use the constructor nowadays.
In other words, you used to be able to do this:
var regexp = new RegExp("pattern");
regexp.compile("new pattern");
But nowadays it is not any different from simply calling:
var regexp = new RegExp("pattern");
regexp = new RegExp("new pattern");
Daniel Lew
2009-05-19 20:12:09
Makes sense. :)
Vilx-
2009-05-19 20:18:33
+2
A:
As far as i can tell all RegExp.compile does is replace the underlying regular expression of a RegExp object. I think compile may have had value in the past, but all modern JS engines "compile" the regex on first call and cache that "compiled" version.
olliej
2009-05-19 20:13:25