Hi,
What will be the regular expression to accept 'CP123' First two letters CP and other 3 or 4 or 5 nos.
thank you.In CP[0-9]{3,5} it gets CP123 but not accepts CP1 or CP72. I want all these to accept CP123, CP1234, CP1, CP34. Thanks
Waheed
2009-05-25 10:59:02
here {x,y} defines the min and the max number of [0-9] to be matched. Change x and y to whatever you want.
Canopus
2009-05-25 11:08:19
If you want the first number to be greater than zero: `CP[1-9][0-9]{2,4}`.
Gumbo
2009-05-25 15:30:04
+1
A:
even if your question it's not very clear this should work:
r'^CP[0-9]{3,5}$'
DrFalk3n
2009-05-25 10:48:01
+6
A:
This will match your requirements:
^CP\d{3,5}$
The ^ matches the beginning of the string, so that it doesn't allow any characters to the left of "CP".
\d matches a digit, {3,5} makes it match 3-5 digits.
The $ matches the end of the string, so that it doesn't allow any characrers after the digits.
If you are using the regular expression in a validation control, you can remove the ^ and $, as that is added by the control:
CP\d{3,5}
Guffa
2009-05-25 10:52:48
The only other variation I can think is if the 'CP' should be case insensitive e.g. ^(?i)CP\d{3,5}$
it depends
2009-05-25 11:03:46
A:
Regex regxExp = new Regex( "CP[0-9]{3,5}" );
bool result = regxExp.IsMatch( //Expression );
Sauron
2009-05-25 10:58:00
+2
A:
As per update in comments:
CP\d{1,5}
if you want one to five digits following CP. Otherwise use
CP\d+
if you just want CP followed by at least one digit.
Brian Rasmussen
2009-05-25 11:03:28