I am creating a chunk of HTML/JavaScript with the below code:
$result = mysql_query("SELECT * FROM posts WHERE userid = '$user_id' ORDER BY DATE desc LIMIT 5")or die (mysql_error());
while ($row = mysql_fetch_array($result))
{
$source = $row[source];
$source = "'$source'";
$p = $p.'<div id="red-div"><div id="smartass"><div id="image"><img src="thumbs/'.$user_image.'" /></div><div id="playsong"><a href="#" onclick="playsong(';
$p = p.$source;
$p = $p.'); return false;"><img src="play.png" width="16" height="16" border="0" /></a>'.$row[artist].' - '.$row[title].'</div></div><div id="post-comment">'.$row[comment].'</div><div id="post-date">'.$row[date].'</div></div><div id="dotted-line"></div>';
}
I then update a part of my page with the following code:
parent.document.getElementById('posts').innerHTML = '<?php echo $p; ?>';
For some reason no matter how I quote or enter $source
into playsong('')
; I loose the ''
in playsong();
resulting in something like playsong(theSongVariable);
and that of course does not work.
How do I properly quote or output the ''
to make sure they stay in playsong('')
;?