echo include in php?

Question

hi, I need to echo an include from my php function. I have tried the below but neither work? Does php support this within a function?

echo "<?php include ('http://www.mysite.com/script.php'); ?>";
echo "include (\"http://www.mysite.com/script.php\");";

Thanks

Answer 1

Echo prints something to the output buffer - it's not parsed by PHP. If you want to include something, just do it

include ('http://www.mysite.com/script.php');

You don't need to print out PHP source code, when you're writing PHP source code.

Answer 2

Have a look at this. http://stackoverflow.com/questions/171318/how-do-i-capture-php-output-into-a-variable

Answer 3

Just do:

include("http://www.mysite.com/script.php");

Or:

echo file_get_contents("http://www.mysite.com/script.php");

Notes:

• This may slow down your page due to network latency or if the other server is slow.
• This requires allow_url_fopen to be on for your PHP installation. Some hosts turn it off.
• This will not give you the PHP code, it'll give you the HTML/text output.

Answer 4

Not really sure what you're asking, but you can't really include something via http and expect to see code, since the server will parse the file.

If "script.php" is a local file, you could try something like:

$file = file_get_contents('script.php');
echo $file;

Answer 5

Shortest way is:

readfile('http://www.mysite.com/script.php');

That will directly output the file.