views:

3483

answers:

8

Given a list of files in files.txt, I can get a list of their sizes like this:

cat files.txt | xargs ls -l | cut -c 23-30

which produces something like this:

  151552
  319488
 1536000
  225280

How can I get the total of all those numbers?

+3  A: 

I would use "du" instead.

$ cat files.txt | xargs du -c | tail -1
4480    total

If you just want the number:

cat files.txt | xargs du -c | tail -1 | awk '{print $1}'
MichaelJones
Disk usage != size of file. du reports disk usage.
0x6adb015
I think the -b switch makes du do what I need.
RichieHindle
@0x6adb015 Good knowledge. Thanks I hadn't realised.
MichaelJones
+10  A: 

Here goes

cat files.txt | xargs ls -l | cut -c 23-30 | 
  awk '{total = total + $1}END{print total}'
Greg Reynolds
Using awk is a fine idea, but why keep the `cut`? That's a predictable column number, so use `... | xargs ls -l | awk '{total = total + $5}{END{print total}' `
dmckee
You are correct of course - it was easier just to append on to the end of what was already there :-)
Greg Reynolds
A: 

Pipe to gawk:

 cat files.txt | xargs ls -l | cut -c 23-30 | gawk 'BEGIN { sum = 0 } // { sum = sum + $0 } END { print sum }'
0x6adb015
+1  A: 

You can use the following script if you just want to use shell scripting without awk or other interpreters:

#!/bin/bash

total=0

for number in `cat files.txt | xargs ls -l | cut -c 23-30`; do
   let total=$total+$number
done

echo $total
Andre Miller
A: 

Here's mine

cat files.txt | xargs ls -l | cut -c 23-30 | sed -e :a -e '$!N;s/\n/+/;ta' | bc
Jason Punyon
+1 for proving once and for all that there are uglier languages than perl :)
bdonlan
+1  A: 

In ksh:

echo " 0 $(ls -l $(<files.txt) | awk '{print $5}' | tr '\n' '+') 0" | bc
Sanjaya R
Good for picking up on skipping the `cut`, but you ignore awks ability to do the math...
dmckee
A: 

Instead of using cut to get the file size from output of ls -l, you can use directly:

$ cat files.txt | xargs ls -l | awk '{total += $5} END {print "Total:", total, "bytes"}'

Awk interprets "$5" as the fifth column. This is the column from ls -l that gives you the file size.

Barun
+1  A: 
#
#       @(#) addup.sh 1.0 90/07/19
#
#       Copyright (C) <heh> SjB, 1990
#       Adds up a column (default=last) of numbers in a file.
#       95/05/16 updated to allow (999) negative style numbers.


case $1 in

-[0-9])

        COLUMN=`echo $1 | tr -d -`

        shift

;;

*)

        COLUMN="NF"

;;

esac

echo "Adding up column .. $COLUMN .. of file(s) .. $*"

nawk  ' OFMT="%.2f"                                       # 1 "%12.2f"

        { x = '$COLUMN'                                   # 2

          neg = index($x, "$")                            # 3

          if (neg > 0) X = gsub("\\$", "", $x)

          neg = index($x, ",")                            # 4

          if (neg > 1) X = gsub(",", "", $x)

          neg = index($x, "(")                            # 8 neg (123 & change

          if (neg > 0) X = gsub("\\(", "", $x)

          if (neg > 0) $x = (-1 * $x)                     # it to "-123.00"

          neg = index($x, "-")                            # 5

          if (neg > 1) $x = (-1 * $x)                     # 6

          t += $x                                         # 7

          print "x is <<<", $x+0, ">>> running balance:", t

        } ' $*


# 1.  set numeric format to eliminate rounding errors
# 1.1 had to reset numeric format from 12.2f to .2f 95/05/16
#     when a computed number is assigned to a variable ( $x = (-1 * $x) )
#     it causes $x to use the OFMT so -1.23 = "________-1.23" vs "-1.23"
#     and that causes my #5 (negative check) to not work correctly because
#     the index returns a number >1 and to the neg neg than becomes a positive
#     this only occurs if the number happened to b a "(" neg number
# 2.  find the field we want to add up (comes from the shell or defaults
#     to the last field "NF") in the file
# 3.  check for a dollar sign ($) in the number - if there get rid of it
#     so we may add it correctly - $12 $1$2 $1$2$ $$1$$2$$ all = 12
# 4.  check for a comma (,) in the number - if there get rid of it so we
#     may add it correctly - 1,2 12, 1,,2 1,,2,, all = 12   (,12=0)
# 5.  check for negative numbers
# 6.  if x is a negative number in the form 999- "make" it a recognized
#     number like -999 - if x is a negative number like -999 already
#     the test fails (y is not >1) and this "true" negative is not made
#     positive
# 7.  accumulate the total
# 8.  if x is a negative number in the form (999) "make it a recognized
#     number like -999
# * Note that a (-9) (neg neg number) returns a postive
# * Mite not work rite with all forms of all numbers using $-,+. etc. *
steven bensky