I know that if I do something like this: class Obj { public: int* nine; }; Obj Obj1; //Awesome name int eight = 8; Obj1.nine = &eight; Obj Obj2 = Obj1; //Another Awesome name then Obj1's and Obj2's nines will point to the same 8, but will they share the same pointer? I.e.: int Necronine = 9; Obj1.nine = &Necronine; Obj2.nine == ...
I know that the compiler sometimes provides a default copy constructor if you don't implement yourself. I am confused about what exactly this constructor does. If I have a class that contains other objects, none of which have a declared copy constructor, what will the behavior be? For example, a class like this: class Foo { Bar bar; }...
This might be a silly question, but... I've been writing a number of classes that utilize non-copyable members. These classes are never initialized via the copy constructor in my source. When I try to compile without supplying my own copy-constructor, g++ throws out many errors about how it can't build a default copy constructor, due ...
I need to copy an object in Java (i.e. copy the object "by value not by reference" so that the new object is not just a reference to the old). I'm weary of implementing clonable and would prefer to use a copy constructor. However, the class I need to copy has MANY member variables that need to be copied (over 100) so adding a new const...
consider the following code: class A { friend class B; friend class C; }; class B: virtual private A { }; class C: private B { }; int main() { C x; //OK default constructor generated by compiler C y = x; //compiler error: copy-constructor unavailable in C y = x; //compiler error: assignment operator unavailable in...