Do PHP closures not have access to parnt function parameters?
Hi, I've been writing some code for PHP 5.3, and I wanted to do something similar to the code I'm showing below. I expect this code to print 'hellohello', but it prints 'hello' instead, and an error. It appears the $inner closure does not have access to the outer function's parameters. Is this normal behavior? Is it a PHP bug? I can't s...