Given a hypoteneuse (c in the typical equation a*a + b*b = c*c), what is an efficient way to calculate all possible integer values of a and b, such that a < b?
Note: I've seen c be greater than 1e12, thus c*c is greater than long.MaxValue, from what I can tell, c*c does fit into a decimal, though.
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A Pythagorean triplet is a set of three natural numbers, a < b < c, for which,
a2 + b2 = c2
For example, 32 + 42 = 9 + 16 = 25 = 52.
There exists exactly one Pythagorean triplet for which a + b + c = 1000.
Find the product abc.
Source: http://projecteuler.net/index.php?section=problems&id=9
I tried but didn't know where my code...
Just as a practice, I am working on an app that solves the famous middle school pythagorean theorem, a squared + b squared = c squared. Unfortunately, the out-coming answer has, in my eyes, nothing to do with the actual answer. Here is the code used during the "solve" action.
- (IBAction)solve {
int legoneint;
int legtwoint;
int hy...
I have a question for everyone. I have this problem statement where in given, x^2 + y^2 = c is the equation, you have to optimally find the tuples (x,y) such that the equation holds true.
Given a variable c, whose value is known, you have to find the values (x,y). So suppose if you have c=0, then x=0 and y=0. Suppose you have c=2, then...