Hello,
I am writing certain code in MIPS and I've come to the point where the requirement is to store the result, temporarily, in HI and LO special registers (both are 8 bytes wide). These instructions are at my disposal:
divu s,t lo <-- s div t ; hi <-- s mod t
multu s,t hi / lo < -- s * t ;
So, divu stores result of divisi...
Trying to convert this c code into MIPS and run it in SPIM.
int A[100], B[100];
for(i=1; i<100; 1++){
A[i] = A[i-1] + B[i];
}
So far this is what I have.
# comments are delimted by has marks
.data
A: .word 0:100 # array of 12 integers
B: .word 0:100 # array of 12 integers
.text
main:
li $v0, 1 # l...
Hey hey,
I am working on a little mini compiler while trying to learn some MIPS here. Here's my issue:
MIPS has an instruction li (load immediate) which would work like this
li $5,100
which would load 100 into register 5.
However, I need to load floats into registers right now and am struggling with figuring out a way to do it...s...
Below is the beginning of a chunk of SPIM code:
.data
a: .space 20
b: .space 20
.text
set_all:
sw $ra,0($sp)
li $t0,0
li $t1,10
............
Unfortunately, the second array I declare ('b') causes the SPIM interpreter to spit out:
spim: (parser) syntax error on line 3
of file spim.out b: .space 20
...
My problem is getting 64 bit key from user. For this I need to get 16 characters as string which contains hexadecimal characters (123456789ABCDEF). I got string from user and I reached characters with the code below. But I dont know how convert character to binary 4 bits. in
.data
insert_into:
.word 8
Ask_Input:
.asciiz...
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