I'm writing a C/Shell program that will be doing su or sudo or ssh. They all want their passwords in consol input rather than stdin. Does anybody know a solution? Setting up password-less sudo is not an option. Expect could be an option, but it's not present on my stripped-down system. ...
How can I su from root to db2inst1 and invoke a SQL script all in 1 line? I am thinking about something like this: su db2inst1 | db2 CONNECT TO myDatabase USER db2inst1 USING mypw; db2 -c -i -w -td@ -f /tmp/deploy/sql/My.sql | exit; Any ideas? ...
Hi, On unix I am working as say user X, and I want to login to user Y from X. Now issue is that I dont want Y's cshrc (or any other login script) to run while I login to his user name. I vaguely remember there used to be a way to do so, something like execute "su" command with some option for not running login scripts, but none of th...
In my shell script (bash) I want to call other shell scripts. I run my script as user_A. One of these scripts needs special handling: It has to be run as different user (user_B). Password needed here. It is interactive, but not only asks questions but runs another script in name of another user (user_C) using su. I have to enter a pass...
I'm writing a bash script which calls a lot of other scripts. Several scripts have to be executed as user_1 but several ones as user_2. The scripts should be called in strict sequence. I start my script as user_1 and use su many times to become user_2. These times su requires a password so I have to retype it many times. I'd like to avoi...
This command has an empty output. su user -c "ABC=abc;echo $ABC" Any idea, how can I define a variable in the input command? ...
In my bash script I execute some commands as other user. I want to call a bash function in command of su I defined in my script before. my_function() { do_something } su username -c "my_function" The above script doesn't work, of course my_function is not defined inside su. I have only the idea to save the function into separate fi...
There is a shell script (/bin/sh, not bash) that requires root permissions for execution. If it is ran by a normal user it should ask user a password to get root access and re-run itself. Now it uses the following code: if [ $(id -u) -ne 0 ]; then su root -- $0 $@ ; ... fi That works fine, but there are some OS like Ubuntu that has n...