I have the following HTML :
<li>
<a class="meuble-tab" href="#">Meuble</a>
</li>
i need to achieve the following:
<li class="active">
<a class="meuble-tab" href="#">Meuble</a>
</li>
Using Jquery I am at the point where i can get to the
$(".meuble-tab")
How do I get to its parent "li" to do the addClass("active")?
...
I have a database with a list of locations e.g.:
C_ID | Name
1 | Italy
2 | Germany
3 | France
4 | Spain
and in a seperate table, a list of people who are from those countries,
P_ID | Name | C_ID
1 | John | 1
2 | Mark | 1
3 | Paul | 2
4 | Pierre | 3
5 | Alan | 2
I have grabbed ...
How do I go from this multidimensional array:
Array (
[Camden Town] => Array (
[0] => La Dominican
[1] => A Lounge
)
[Coastal] => Array (
[0] => Royal Hotel
)
[Como] => Array (
[0] => Casa Producto
[1] => Casa Wow
)
[Florence] => Array (
[0] => Florenciana Hotel
)
)
to this
<ul>
Camden Tow...
I'm building a very simplistic unordered list tree in XHTML with multiple levels deep. The way it works is that you click a parent node, and it uses the jQuery .load() API to make an AJAX call back to the server to see if this node has children. If it does, it inserts those nodes inside. When you click the parent link again, it does a .r...
Basically I want to control the margin on the left of the list. Here's how I have it structured:
<li>
<a href="http://link.com">Main</a>
<ul>
<li>
<a href="http://link.com" title="">Sub1</a>
</li>
<li>
<a href="http://link.com" title="">Sub2</a>
</li>
</ul>
</li>
The sub-sections are ...
This is super handy for some problems:
>>> re.search('(?P<b>.b.).*(?P<i>.i.)', 'abcdefghijk').groupdict()
{'i': 'hij', 'b': 'abc'}
But what if I don't know what order to expect ahead of time?
[update]
Eg, say I have an input variable containing some unknown order of characters and it just so happens that 'b' comes after 'i'. I wa...
I have the following SQL table:
A|B
---
w|x
x|w
y|z
z|y
Can I construct a query which will yield the following result:
A|B
---
w|x
y|z
To summarize, I would like to treat the two columns as an unordered set, such that (a,b) == (b,a).
...
I'm really frustrated with this one. A few weeks ago I got it working in both firefox and ie just fine. Went back today to do some testing and found a problem with the display in firefox and I've been searching the code but can't find anything. I could use a few tips from anyone willing, I'm sure I'm looking at the wrong things. I up...
Is it possible to render a TreeViewControl as an unordered list instead of a table?
...
I have an unordered list, each list item has an id (id="6~OriginalName") - when I do a toArray on this list, I get a nice array and each item looks like "6~OriginalName" that I can parse later on.
$("#roleList").sortable('toArray')
The problem is that now I've embedded a TextBox in each list, which its value that of the OriginalName, ...