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A way to strip returned values from java.io.File.listFiles in Clojure

Answer 1

+7 A:

Those strings are just the print format for a Java File object.

See the File javadoc for which operations are available.

If you want the file paths as strings, it would be something like

(map #(.getPath %) 
  (.listFiles (io/file "/home/loluser/loldir")))

Or you could just use list, which returns strings in the first place:

(.list (io/file "/home/loluser/loldir"))

If you want to read the file, you might as well keep it as a File object to pass into the core slurp or other clojure.java.io or clojure.contrib.duck-streams functions.

j-g-faustus 2010-07-06 20:59:50

Could I pass the File object to slurp like this: (slurp (first (.listFiles (io/file "/home/loluser/loldir")))) or maybe put it into a var first and then do a slurp of the var?

bleakgadfly 2010-07-06 21:12:54

Yes. Although listFiles returns both files and directories, so you would probably want to filter with #(.isFile %) first.

j-g-faustus 2010-07-06 21:24:41

As an aside, note the mangled syntax highlighting.

Svante 2010-07-06 21:42:51

@j-g-faustus: Is there a way to sort the files in the map by lastModified date?

bleakgadfly 2010-07-13 15:00:16

Sure: `(sort-by #(.lastModified %) (.listFiles (io/file "/etc")))` http://richhickey.github.com/clojure/clojure.core-api.html#clojure.core/sort-by

j-g-faustus 2010-07-13 22:37:29

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A way to strip returned values from java.io.File.listFiles in Clojure

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