How can I cast an Object to an int in java?
You have to cast it to an Integer (int's wrapper class). You can then use Integer's intValue() method to obtain the inner int.
Assuming the object is an Integer
object, then you can do this:
int i = ((Integer) obj).intValue();
If the object isn't an Integer
object, then you have to detect the type and convert it based on its type.
You can't. An int is not an Object.
Integer is an object though, but I doubt that's what you mean.
Can't be done. An int
is not an object, it's a primitive type. You can cast it to Integer, then get the int.
Integer i = (Integer) o; // throws ClassCastException if o.getClass() != Integer.class
int num = i; //Java 1.5 or higher
If you mean cast a String to int, use Integer.valueOf("123")
.
You can't cast most other Objects to int though, because they wont have an int value. E.g. an XmlDocument has no int value.
If you're sure that this object is an Integer
:
int i = (Integer) object;
Beware, it can throw a ClassCastException
if your object isn't an Integer
and a NullPointerException
if your object is null
.
This way you assume that your Object is an Integer (the wrapped int) and you unbox it into an int.
int
is a primitive so it can't be stored as an Object
, the only way is to have an int
considered/boxed as an Integer
then stored as an Object
.
If your object is a String
, then you can use the Integer.valueOf()
method to convert it into a simple int :
int i = Integer.valueOf((String) object);
It can throw a NumberFormatException
if your object isn't really a String
with an integer as content.
Resources :
On the same topic :
If the Object
was originally been instantiated as an Integer
, then you can downcast it to an int
using the cast operator (Subtype)
.
Object object = new Integer(10);
int i = (Integer) object;
Note that this only works when you're using at least Java 1.5 with autoboxing feature, otherwise you have to declare i
as Integer
instead and then call intValue()
on it.
But if it initially wasn't created as an Integer
at all, then you can't downcast like that. It would result in a ClassCastException
with the original classname in the message. If the object's toString()
representation as obtained by String#valueOf()
denotes a syntactically valid integer number (e.g. digits only, if necessary with a minus sign in front), then you can use Integer#valueOf()
or new Integer()
for this.
Object object = "10";
int i = Integer.valueOf(String.valueOf(object));
See also:
Answer:
int i = ( Integer ) yourObject;
If, your object is an integer already, it will run smoothly. ie:
Object yourObject = 1;
// cast here
or
Object yourObject = new Integer(1);
// cast here
etc.
If your object is anything else, you would need to convert it ( if possible ) to an int first:
String s = "1";
Object yourObject = Integer.parseInt(s);
// cast here
Or
String s = "1";
Object yourObject = Integer.valueOf( s );
// cast here
int i = (Integer) object; //Type is Integer.
int i = Integer.parseInt((String)object); //Type is String.
@Deprecated
public static int toInt(Object obj)
{
if (obj instanceof String)
{
return Integer.parseInt((String) obj);
} else if (obj instanceof Integer)
{
return ((Integer) obj).intValue();
} else
{
String toString = obj.toString();
if (toString.matches("-?\d+"))
{
return Integer.parseInt(toString);
}
throw new IllegalArgumentException("This Object doesn't represent an int");
}
}
As you can see, this isn't a very efficient way of doing it. You simply have to be sure of what kind of object you have. Then convert it to an int the right way.
I guess you're wondering why C or C++ lets you manipulate an object pointer like a number, but you can't manipulate an object reference in Java the same way.
Object references in Java aren't like pointers in C or C++... Pointers basically are integers and you can manipulate them like any other int. References are intentionally a more concrete abstraction and cannot be manipulated the way pointers can.