Remove end of line characters from Java string

Question

I have string like this

"hello
java
book"

I want remove \r and \n from string(hello\r\njava\r\nbook). I want string as "hellojavabook". How can i do this?

Answer 1

Given a String str:

str = str.replaceAll("\\\\r","")
str = str.replaceAll("\\\\n","")

Answer 2

Have you tried using the replaceAll method to replace any occurence of \n or \r with the empty String?

Answer 3

str = "hello java book" str.replaceAll("\r", "") str.replaceAll("\n", "")

Not that I know java or anything, but I got the info from Google in less than 2 seconds.

http://java.sun.com/j2se/1.4.2/docs/api/java/lang/String.html#replaceAll(java.lang.String,%20java.lang.String)

Answer 4

Regex with replaceAll.

public class Main
{
    public static void main(final String[] argv) 
    {
        String str;

        str = "hello\r\njava\r\nbook";
        str = str.replaceAll("(\\r|\\n)", "");
        System.out.println(str);
    }
}

If you only want to remove \r\n when they are pairs (the above code removes either \r or \n) do this instead:

str = str.replaceAll("\\r\\n", "");

Answer 5

If you want to avoid the regex, or must target an earlier JVM, String.replace() will do:

str=str.replace("\r","").replace("\n","");

And to remove a CRLF pair:

str=str.replace("\r\n","");

The latter is more efficient than building a regex to do the same thing. But I think the former will be faster as a regex since the string is only parsed once.

Answer 6

static byte[] discardWhitespace(byte[] data) {
    byte groomedData[] = new byte[data.length];
    int bytesCopied = 0;

    for (int i = 0; i < data.length; i++) {
        switch (data[i]) {
            case (byte) '\n' :
            case (byte) '\r' :
                break;
            default:
                groomedData[bytesCopied++] = data[i];
        }
    }

    byte packedData[] = new byte[bytesCopied];

    System.arraycopy(groomedData, 0, packedData, 0, bytesCopied);

    return packedData;
}

Code found on commons-codec project.