I auto generated an xsd file from the below xml and used xsd2code to get a c# class. The problem is the entire xml doesn't deserialize.
Here is how I'm attempting to deserialize:
static void Main(string[] args)
{
using (TextReader textReader = new StreamReader("config.xml"))
{
// string temp = text...
Hello,
I looked at this thread to find out how to insert XML into XML with XSLT http://stackoverflow.com/questions/862954/insert-xml-node-at-a-specific-position-of-an-existing-document
But I have a problem since I need to insert XML between two grand child nodes.
For example I want to insert <s>...</s> between <r>...</r> and <t>...</t>...
Let's say I have a series of xml files in this format:
A.xml:
<page>
<header>Page A</header>
<content>blAh blAh blAh</content>
</page>
B.xml:
<page also-include="A.xml">
<header>Page B</header>
<content>Blah Blah Blah</content>
</page>
Using this XSLT:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.o...
I have an XML file that I want to sort by an attribute. The file is structured as shown below:
<wb xmlns:cf="http://www.macromedia.com/2004/cfform">
<a:form name="chart">
<a:input FIELDNUMBER="09" INDEX="2" LEFT="200" />
<a:input FIELDNUMBER="08" INDEX="3" LEFT="200" />
<a:fieldset FIELD="a" FIELDNAME...
Hi!
I apologize ahead of time if I am not asking this properly.. it is hard to put into words what I am asking..
I have XForms model such as:
<file>
<criteria>
<criterion></criterion>
</criteria>
</file>
I want to have multiple input text boxes that create a new criterion tag.
user interface such as:
<xf:input ref=...
Ok, following on from my question here.
Lets say my pages are now like this:
A.xml:
<page>
<header>Page A</header>
<content-a>Random content for page A</content-a>
<content-b>More of page A's content</content-b>
<content-c>More of page A's content</content-c>
<!-- This doesn't keep going: there are a predefined num...
Hi,
I'm working on a project for the iPad, I need to read and write to an xml file, which is also used by the counter part of the application in windows.
The problem that I have is that I've been looking around but I haven't found a way to modify an element or attribute in an xml, without having to build the whole xml again.
I saw thi...
How do I parse an xml document as a stream using Scala?
I've used the Stax API in java to accomplish this, but I'd like to know if there is a "scala" way to do this.
...
hi all,
I'm using jQuery to parse some XML, like so:
function enumOptions(xml) {
$(xml).find("animal").each(function(){
alert($(this).text());
});
}
enumOptions("<root><animal>cow</animal><animal>squirrel</animal></root>");
This works great. However if I try and look for nodes called "option" then it doesn't work:
fu...
This could just be a syntax error, but I'm trying to create a Document object from scratch, starting with document.implementation.createDocument() and then using jquery's append() method to add the elements. But it's not appending:
var myDoc = document.implementation.createDocument("", 'stuff', null);
$("stuff",myDoc).attr("test","test...
In my PHP code I have this:
$filename = 'data.xml';
$xml = file_get_contents($filename);
$data = simplexml_load_string($xml);
$variable = "";
foreach ($data->file_info as $record)
{
$id1 = $record['id1'];
$id2 = $record['id2'];
}
And it works perfectly fine on the web server, but when trying to view it locally (using xampp) I ...
Suppose I have a XSL as follows:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="html" encoding="utf-8" omit-xml-declaration="yes" indent="yes"/>
<xsl:param name="sortKey" select="'firstname'"/>
</xsl:stylesheet>
Then a XML as follows
<?xml version="1.0" encoding="UTF-8"...
kXML is an alternative XML parser I chose to use for JavaME apps.
The XML file to be editted is inside the mobile app's own JAR.
I'm using CLDC profile.
Please help
...
I have this code that works perfectly in Java SE. How can I make it work in JavaME?
These classes are not available in Java ME, CLDC profile.
DocumentBuilder, DocumentBuilderFactory, NodeList, DOMSource, StreamResult,
TransformerFactory, Transformer.
` DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
try{
...
I have the following object:
public class MyClass
{
public int Id { get; set;}
public string Name { get; set; }
}
I'm wanting to serialize this to the following xml string:
<MyClass>
<Id>1</Id>
<Name>My Name</Name>
</MyClass>
Unfortunately, when I use the XMLSerializer I get a string which looks like:
<?xml versi...
Hi,
I have an XML document with this structure:
<Fruits>
<Fruit>
<Code>1</Code>
<Name>Apple</Name>
</Fruit>
</Fruits>
What is the best way to get a <Fruit> element by its code (or any other field) in PowerShell 1 code?
(Not XPath, as it is supported in PowerShell 2 only)
Thanks!
...
Just curious as to why Dictionary is not supported by XmlSerializer?
You can get around it easily enough by using DataContractSerializer and writing the object to a XmlTextWriter, but what are the characteristics of a Dictionary that makes it difficult for a XmlSerializer to deal with considering it's really an array of KeyValuePairs.
...
hi,
I have an XML file which I'd like to query (read/write) in the same way as I would a relational database. Performance is not a big issue, I just want to be able to load the file and start querying, preferably without having to define a schema. Does anyone know if such software exists?
...
In Visual Studio, I have an XML file (with .xml extension) which contains an XML fragment that I use in my program:
<tag1>
data
...
</tag1>
<tag2>
data
...
</tag2>
Visual Studio shows me an error in the error list: "XML document cannot contain multiple root level elements".
But this is not a complete document, just a fragment that ...
Let's consider the following XML Schema:
<?xml version="1.0" encoding="UTF-8"?>
<schema
targetNamespace="http://www.example.org/library"
elementFormDefault="qualified"
xmlns="http://www.w3.org/2001/XMLSchema"
xmlns:lib="http://www.example.org/library">
<element name="library" type="lib:libraryType"></element>...