views:

726

answers:

4

I am applying a ViewerFilter to a tree of a few branches, but mostly leaves. The filter really applies to the leaves, using properties within the leaf. All branches are left untouched so that their leafs can appear.

However I would like to filter out branches that contain no selected leafs, and I can see no mechanism within ViewerFilter that allows this.

Is this possible at all?

For example, given the notional tree below (where b is a branch, a L is a leaf)

b0
  b1
    L2
    L4
    L8
  b2
    L1
    L3
    L5

I would like to apply a ViewerFilter that selects only even leafs, and selects only branches that contain even leafs. The resulting tree would be ..

b0
  b1
    L2
    L4
    L8

.. where branch b2 does not display as it contains no selected children, but branches b0 and b1 do.

M.

A: 

I'm not sure what you mean by selected leaves. If you mean selected in the view, you can find this out by calling Viewer.getSelection(). The select method that you implement in your filter passes in the viewer, parent, and leaf. You should be able to use this information to decide if the leaf is selected or not and filter them out. If you can give some more information, I can probably answer with more detail.

AdamC
Martin Cowie
In that case, in the select method, you will need to look recursively starting the element, getting its children until you reach an even leaf(return true) or the end (return false).
AdamC
A: 
class MyFilter extends ViewerFilter{
  private boolean isLeaf(Object element){
     // implement this
  }

  private boolean isEvenLeaf(Object leaf){
     // implement this
  }

  @Override
  public boolean select(Viewer viewer, Object parentElement, Object element){
     if(isLeaf(element))
        return isEventLeaf(element);
     else{
       StructuredViewer sviewer = (StructuredViewer)viewer;
       ITreeContentProvider provider = (ITreeContentProvider)viewer.getContentProvider();
       for(Object child: provider.getChildren(element)){
         if(select(viewer, element, child))
           return true;
       }
       return false;
    }
  }
}
Santhosh Kumar T
A: 

Yes, if you don't filter out the branch nodes, they'll be shown even if there are no leaves in it. If you want the filter to be permanently on, something you can consider is using the ITreeContentProvider as a filter.

Since the content provider has both getChildren() and hasChildren() methods, you have a little more control.

thehiatus
A: 

The approach is exactly what I needed. THX for your posting.

Pretor